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= 3\pi r^2 - Blask

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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Comparing coefficients with \( ax^2 + bx + c \), we identify:
\( b = -6a \)
\( c = 9a - 5 \)
But we are given \( b = -6 \), so:
-6a = -6 \Rightarrow a = 1
Now substitute \( a = 1 \) into the expression for \( c \):
c = 9(1) - 5 = 4
Alternatively, using the relationship \( c = 9a - 5 \) and \( a = 1 \)...
c = 9a - 5
But under the condition \( b = -6 \), this fixes \( a = 1 \), hence \(...

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