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Home » Let width = \(w\), length = \(3w\). - Blask

Let width = \(w\), length = \(3w\). - Blask

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 7d = 1680 \Rightarrow d = 240

📌 #### #### 240

📌 Solve for \( x \): \( 2x^2 - 16x + 30 = 0 \).

📌 Use the quadratic formula: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a = 2\), \(b = -16\), \(c = 30\).

📌 Discriminant:

📌 b^2 - 4ac = (-16)^2 - 4 \times 2 \times 30 = 256 - 240 = 16

📌 x = \frac{16 \pm \sqrt{16}}{4} = \frac{16 \pm 4}{4}

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