Solution: The hypotenuse is $\sqrt9^2 + 12^2 = 15$ cm. $\sin \theta = \frac{\textopposite}{\texthypotenuse} = \frac915 = \frac35$.

Solution: The hypotenuse is $\sqrt9^2 + 12^2 = 15$ cm. $\sin \theta = \frac{\textopposite}{\texthypotenuse} = \frac915 = \frac35$. - Blask

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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