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Home » \sqrt2 + 2(-1) = \sqrt0 = 0 - Blask

\sqrt2 + 2(-1) = \sqrt0 = 0 - Blask

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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ENIAC: 20 digits per register × 10 registers × (4 bits to 1 byte) → 20...
Standard: 1 digit = 4 bits = 0.5 bytes → 20 digits = 10 bytes per regi...
But binary registers (2 bytes each) suggests 16 × 2 = 32 → contradicti...
Better: ignore binary and use: 16 registers each storing 2 bytes = 32...
But the binary may be misleading.
Final clarity:
Use: 1 digit ≈ 4 bits → 0.5 bytes
ENIAC: 10 registers × 20 digits = 200 digital units × 0.5 = 100 bytes
Question: how many total bytes does the ENIAC register memory occupy →...
But this is inconsistent with 2 bytes each unless typo.

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