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Home » You Won’t Believe What Schleprock Can Do—Spoiler: It’s Insane! - Blask

You Won’t Believe What Schleprock Can Do—Spoiler: It’s Insane! - Blask

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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Since none of the rational roots work, we proceed with finding roots u...
Consider \( g(x) = x^3 - 4x + 2 \). The derivative is:
g'(x) = 3x^2 - 4
Setting \( g'(x) = 0 \):
3x^2 - 4 = 0 \implies x^2 = \frac{4}{3} \implies x = \pm \frac{2}{\sqr...
Evaluate \( g(x) \) at these critical points:
At \( x = \frac{2}{\sqrt{3}} \):
g\left(\frac{2}{\sqrt{3}}\right) = \left(\frac{8}{3\sqrt{3}}\right) -...
This is negative, and at \( x = -\frac{2}{\sqrt{3}} \), it's positive....
Alternatively, use cubic formula or numerical solvers:

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